Skip to contentSkip to footer

Developer Android Interview Questions

Salaries
Interviews

10,446 developer android interview questions shared by candidates

The remote coderpad challenge was to map some json to an object. The json object contained a part of a url path and had children with deeper parts of the path and so on. Had to write an algorithm to traverse the object's tree and print all full paths.
avatar

Android Developer

Interviewed at Groupon

2.9★
Oct 4, 2019

The remote coderpad challenge was to map some json to an object. The json object contained a part of a url path and had children with deeper parts of the path and so on. Had to write an algorithm to traverse the object's tree and print all full paths.

Fibonacci Series: The Fibonacci Sequence is the series of numbers where the next number is found by adding up the two numbers before it. F(0) = 0 F(1) = 1 F(n) = F(n-1) + F(n-2) Which of the following is the correct and the most efficient implementation for fibonacci numbers. int fib(int n) { int f[n+1]; int i; f[0] = 0; f[1] = 1; for (i = 2; i <= n; i++) { f[i] = f[i-1] + f[i-2]; } return f[n]; } int fib(int n) { int f[n+1]; int i; if( n <= 1) return n; f[0] = 0; f[1] = 1; for (i = 2; i < n; i++) { f[i] = f[i-1] + f[i-2]; } return f[n]; } int fib(int n) { if (n <= 1) return n; return fib(n-1) + fib(n-2); } int fib(int n) { int a = 0, b = 1, c, i; if( n == 0) return a; for (i = 2; i <= n; i++) { c = a + b; a = b; b = c; } return b; }
avatar

Android Developer

Interviewed at Smartprix

3.4★
Aug 3, 2016

Fibonacci Series: The Fibonacci Sequence is the series of numbers where the next number is found by adding up the two numbers before it. F(0) = 0 F(1) = 1 F(n) = F(n-1) + F(n-2) Which of the following is the correct and the most efficient implementation for fibonacci numbers. int fib(int n) { int f[n+1]; int i; f[0] = 0; f[1] = 1; for (i = 2; i <= n; i++) { f[i] = f[i-1] + f[i-2]; } return f[n]; } int fib(int n) { int f[n+1]; int i; if( n <= 1) return n; f[0] = 0; f[1] = 1; for (i = 2; i < n; i++) { f[i] = f[i-1] + f[i-2]; } return f[n]; } int fib(int n) { if (n <= 1) return n; return fib(n-1) + fib(n-2); } int fib(int n) { int a = 0, b = 1, c, i; if( n == 0) return a; for (i = 2; i <= n; i++) { c = a + b; a = b; b = c; } return b; }

Viewing 61 - 70 interview questions

Glassdoor has 10,446 interview questions and reports from Developer android interviews. Prepare for your interview. Get hired. Love your job.