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It was a puzzle Two people, let "A" and "B" are talking. "C" tries to listen to them. "A' says to "B", I have 3 daughters, the product of their age is 72. Can you tell their age? "B", says "NO". "A" again said to B about some of his daughter's age. "C" could not hear the sum. A asked to B Can you tell their age now. "B" again said NO. They "A" says my eldest daughter's age is equal to my house's street number. B immediately answered A about the age. What was their ages?
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Software Engineer

Interviewed at Bounteous x Accolite

3.3★
May 9, 2013

It was a puzzle Two people, let "A" and "B" are talking. "C" tries to listen to them. "A' says to "B", I have 3 daughters, the product of their age is 72. Can you tell their age? "B", says "NO". "A" again said to B about some of his daughter's age. "C" could not hear the sum. A asked to B Can you tell their age now. "B" again said NO. They "A" says my eldest daughter's age is equal to my house's street number. B immediately answered A about the age. What was their ages?

Implement a function all_anagram_groups() that, given many input strings, will identify and group words that are anagrams of each other. An anagram is word that is just a re-arrangement of the characters of another word, like "reap" and "pear" and "a per" (whitespace is ignored). But "pear" and "rep" are not, since "rep" does not have an "a". Also, "the" and "thee" are not anagrams, because "the" only has one "e". Given this example input: [ "pear","dirty room","amleth","reap","tinsel","hamlet","dormitory","listen","silent" ] The output should be an array-of-arrays (or list-of-lists) [ ["pear","reap"], ["dirty room","dormitory"], ["amleth","hamlet"], ["tinsel","listen","silent"] ]
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Software Developer - (Willing to Learn Perl)

Interviewed at Booking.com

4.1★
Aug 25, 2014

Implement a function all_anagram_groups() that, given many input strings, will identify and group words that are anagrams of each other. An anagram is word that is just a re-arrangement of the characters of another word, like "reap" and "pear" and "a per" (whitespace is ignored). But "pear" and "rep" are not, since "rep" does not have an "a". Also, "the" and "thee" are not anagrams, because "the" only has one "e". Given this example input: [ "pear","dirty room","amleth","reap","tinsel","hamlet","dormitory","listen","silent" ] The output should be an array-of-arrays (or list-of-lists) [ ["pear","reap"], ["dirty room","dormitory"], ["amleth","hamlet"], ["tinsel","listen","silent"] ]

/* You have rating (0-10) of the hotels per user in this format: scores = [ {'hotel_id': 1001, 'user_id': 501, 'score': 7}, {'hotel_id': 1001, 'user_id': 502, 'score': 7}, {'hotel_id': 1001, 'user_id': 503, 'score': 7}, {'hotel_id': 2001, 'user_id': 504, 'score': 10}, {'hotel_id': 3001, 'user_id': 505, 'score': 5}, {'hotel_id': 2001, 'user_id': 506, 'score': 5} ] Any given hotel might have more than one score. Implement a function, get_hotels(scores, min_avg_score) that returns a list of hotel ids that have average score equal to or higher than min_avg_score. get_hotels(scores, 5) -> [1001, 2001, 3001] get_hotels(scores, 7) -> [1001, 2001] */
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Software Developer

Interviewed at Booking.com

4.1★
Jul 5, 2016

/* You have rating (0-10) of the hotels per user in this format: scores = [ {'hotel_id': 1001, 'user_id': 501, 'score': 7}, {'hotel_id': 1001, 'user_id': 502, 'score': 7}, {'hotel_id': 1001, 'user_id': 503, 'score': 7}, {'hotel_id': 2001, 'user_id': 504, 'score': 10}, {'hotel_id': 3001, 'user_id': 505, 'score': 5}, {'hotel_id': 2001, 'user_id': 506, 'score': 5} ] Any given hotel might have more than one score. Implement a function, get_hotels(scores, min_avg_score) that returns a list of hotel ids that have average score equal to or higher than min_avg_score. get_hotels(scores, 5) -> [1001, 2001, 3001] get_hotels(scores, 7) -> [1001, 2001] */

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