Find number of ones in an integer.
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Write a function(int[]) -> int that returns the lowest unassigned integer. For example [] -> 1 (empty set), [1] -> 2, [5, 3, 1] -> 2. Basically just sort the array, iterate, and compare current and previous. If there is a gap then that's your number.
If you have an unsorted array of numbers from 1-100, except 1 of those numbers is missing, how do you determine which number is missing
Print a binary tree by vertical level order like 1 2 4 3 5 print : 3 2 1 5 4
given an array of numbers to remove the duplicates
If you had a list of appointments (each appointment has a begin time, an end time, and a boolean hasConflict), how would you efficiently go through them and set the hasConflict boolean for each. You cannot assume they are sorted in any way. Keep in mind that one appointment may be very long, etc.
Phone interview question: Given a string pattern of 0s, 1s, and ?s (wildcards), generate all 0-1 strings that match this pattern. e.g. 1?00?101 -> [10000101, 10001101, 11000101, 11001101]. You can generate the strings in any order that suits you.
Given n sets of choices: (1,2,3), (2,3,4), (4,5) You pick one element from each set of choices. Generate all possible picking.
Consider an X x Y array of 1's and 0s. The X axis represents "influences" meaning that X influences Y. So, for example, if $array[3,7] is 1 that means that 3 influences 7. An "influencer" is someone who influences every other person, but is not influenced by any other member. Given such an array, write a function to determine whether or not an "influencer" exists in the array.
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