Full Stack Developer Interview Questions

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There are no particular qns but they randomly ask any program they thought at that time we have to write the program and need to execute it before them. In two technical round I participated one in virtual mode and the other in physical mode. But there need to be lot of preparation for it they only see our coding knowledge and little speaking skills
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Full Stack Developer

Interviewed at Snovasys

4.9
Dec 31, 2023

There are no particular qns but they randomly ask any program they thought at that time we have to write the program and need to execute it before them. In two technical round I participated one in virtual mode and the other in physical mode. But there need to be lot of preparation for it they only see our coding knowledge and little speaking skills

given an array of integers, without reordering, determine the maximum difference between any element and prior smaller element. If there is never a lower prior element, return -1. example arr = [5,3,6,7,4] there are no earlier elements than arr[0]. there is no earlier reading with a value lower than arr[1]. there are two lower earlier readings with a value lower than arr[2]=6: • arr[2] - arr[1] = 6 - 3 = 3 • arr[2] - arr[0] = 6 - 5 = 1 there are three lower earlier readings with a lower value than arr[3]=7: • arr[3] - arr[2] = 7 - 6 = 1 • arr[3] - arr[1] = 7 - 3 =4 • arr[3] - arr[0] = 7 - 5 =2 there is one lower earlier reading with a lower value than arr[4]=4: • arr[4] - arr[1] = 4 - 3 = 1 the maximum trailing record is arr[3] - arr[1] = 4
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Full Stack Developer

Interviewed at webiks

3.1
Jan 5, 2024

given an array of integers, without reordering, determine the maximum difference between any element and prior smaller element. If there is never a lower prior element, return -1. example arr = [5,3,6,7,4] there are no earlier elements than arr[0]. there is no earlier reading with a value lower than arr[1]. there are two lower earlier readings with a value lower than arr[2]=6: • arr[2] - arr[1] = 6 - 3 = 3 • arr[2] - arr[0] = 6 - 5 = 1 there are three lower earlier readings with a lower value than arr[3]=7: • arr[3] - arr[2] = 7 - 6 = 1 • arr[3] - arr[1] = 7 - 3 =4 • arr[3] - arr[0] = 7 - 5 =2 there is one lower earlier reading with a lower value than arr[4]=4: • arr[4] - arr[1] = 4 - 3 = 1 the maximum trailing record is arr[3] - arr[1] = 4

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