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DSA and React Debugging round : Question on String with Backtracking. Major discussion was on approach and then space/time complexity. Mathematical proof for same was discussed. For react debugging, a problem statement about photo rotation was discussed. Google search was allowed in the round.
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Software Engineer - Full Stack

Interviewed at Morphle Technologies

4.3★
Aug 20, 2024

DSA and React Debugging round : Question on String with Backtracking. Major discussion was on approach and then space/time complexity. Mathematical proof for same was discussed. For react debugging, a problem statement about photo rotation was discussed. Google search was allowed in the round.

Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0. Note: the solution set must not contain duplicate triplets. Input: nums = [-1,0,1,2,-1,-4] Output: [[-1,-1,2],[-1,0,1]] Explanation: nums[0] + nums[1] + nums[2] = (-1) + 0 + 1 = 0. nums[1] + nums[2] + nums[4] = 0 + 1 + (-1) = 0. nums[0] + nums[3] + nums[4] = (-1) + 2 + (-1) = 0. The distinct triplets are [-1,0,1] and [-1,-1,2].
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Full Stack Software Engineer

Interviewed at Costco Wholesale

3.9★
Jul 16, 2024

Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0. Note: the solution set must not contain duplicate triplets. Input: nums = [-1,0,1,2,-1,-4] Output: [[-1,-1,2],[-1,0,1]] Explanation: nums[0] + nums[1] + nums[2] = (-1) + 0 + 1 = 0. nums[1] + nums[2] + nums[4] = 0 + 1 + (-1) = 0. nums[0] + nums[3] + nums[4] = (-1) + 2 + (-1) = 0. The distinct triplets are [-1,0,1] and [-1,-1,2].

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