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Written Test: min and max in an array remove duplicates from a string without using extra memory integer between 0 to 999999 will be given , we need to print them in words like for 120 print one hundred twenty JMS queues find out the winner of the tic-tac game board of any size. write the data coming from the DB to a file using multiple threads MCQs were very easy
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Senior Software Developer (Java)

Interviewed at DBS Bank

3.8★
Aug 21, 2016

Written Test: min and max in an array remove duplicates from a string without using extra memory integer between 0 to 999999 will be given , we need to print them in words like for 120 print one hundred twenty JMS queues find out the winner of the tic-tac game board of any size. write the data coming from the DB to a file using multiple threads MCQs were very easy

1) Write a query to rank order the following table in MySQL by votes, display the rank as one of the columns. CREATE TABLE votes ( name CHAR(10), votes INT ); INSERT INTO votes VALUES ('Smith',10), ('Jones',15), ('White',20), ('Black',40), ('Green',50), ('Brown',20);
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Senior Java Engineer

Interviewed at Wallet Hub

4.2★
Jan 27, 2017

1) Write a query to rank order the following table in MySQL by votes, display the rank as one of the columns. CREATE TABLE votes ( name CHAR(10), votes INT ); INSERT INTO votes VALUES ('Smith',10), ('Jones',15), ('White',20), ('Black',40), ('Green',50), ('Brown',20);

I have a table for bugs from a bug tracking software; let’s call the table “bugs”. The table has four columns (id, open_date, close_date, severity). On any given day a bug is open if the open_date is on or before that day and close_date is after that day. For example, a bug is open on “2012-01-01”, if it’s created on or before “2012-01-01” and closed on or after “2012-01-02”. I want an SQL to show the number of bugs open each day for a range of dates. Hint: There are bugs that were never closed.
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Senior Java Engineer

Interviewed at Wallet Hub

4.2★
Jan 27, 2017

I have a table for bugs from a bug tracking software; let’s call the table “bugs”. The table has four columns (id, open_date, close_date, severity). On any given day a bug is open if the open_date is on or before that day and close_date is after that day. For example, a bug is open on “2012-01-01”, if it’s created on or before “2012-01-01” and closed on or after “2012-01-02”. I want an SQL to show the number of bugs open each day for a range of dates. Hint: There are bugs that were never closed.

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